Circle theorems connect radii, chords, tangents and secants. Their usefulness comes from a small set of relationships that can be justified through congruent or similar triangles. The fixed radius determines relationships among the chords, tangents and secants that meet the circle.
This page focuses on length relationships and their proofs. Angles in Circles develops the angle-and-arc rules. The centre, radius and equation of a coordinate circle are treated in Circles in Coordinate Geometry.
On this page
The vocabulary identifies the configuration
A radius joins the centre to a point on the circle. A chord joins two points on the circle. A diameter is a chord through the centre. A secant is a line meeting the circle at two distinct points, while a tangent meets it at one point.
The same infinite line may have an external segment and a segment inside the circle. When a theorem uses a whole secant length, that length begins at the external point and ends at the far circle intersection. It is not just the part inside the circle.
A perpendicular from the centre bisects a chord
Let be a non-diameter chord and let the perpendicular from centre meet it at . The right triangles and have equal hypotenuses , because both are radii, and the common leg . RHS congruence gives .
Conversely, if is the midpoint of a non-diameter chord, then is perpendicular to the chord. For a diameter, the centre is already its midpoint because the two halves are radii. The centre and midpoint then coincide, so they do not determine a unique line.
A perpendicular radius bisects a chord
Diagram explanation and exact data
A=(−4,3), B=(4,3) and O=(0,0). Both radii have length 5. RHS congruence of OMA and OMB proves the chord-bisection relationship without reading lengths from the drawing.
| Measure | Value |
|---|---|
| Radius | |
| Centre-to-chord distance | |
| Half-chord | |
| Chord |
Finding a chord length
A circle has radius , and a chord is from the centre. Half the chord is a leg of a right triangle:
The common error is to stop at , which gives only half the required length. The chord lies inside a diameter of length , so an result is plausible.
In the same circle, or in equal-radius circles, equal chords have equal perpendicular distances from the centre, and conversely. A chord closer to the centre is longer. The same-radius condition matters: equal lengths in different-sized circles do not determine equal central distances.
A tangent is perpendicular to its radius
At a point of tangency , the radius is perpendicular to the tangent line. Another line through that is not perpendicular passes through the circle’s interior and meets the circle again. The perpendicular therefore identifies the tangent direction.
If an external point is from the centre of a radius- circle, a tangent segment has length
The right angle is at , so is the hypotenuse. It is not correct to label the tangent segment as the hypotenuse just because it is outside the circle.
Tangents from one external point are equal
Suppose and are tangents from the same external point to one circle. The triangles and are right-angled, have common hypotenuse and equal radius legs . They are congruent by RHS, so
If the lengths are and , then gives . Each tangent segment is units. Tangents drawn from two different external points do not generally have equal lengths.
Intersecting chords
If chords and intersect at an interior point , then
To see why, compare and . Their angles at are vertically opposite. Their other matching angles are inscribed angles subtending the same arcs. The triangles are similar, so , which gives the product equation.
If , and , then and . Each product uses the two pieces of a single chord, not adjacent segments chosen by appearance.
Secants and the tangent-secant theorem
Let be outside the circle. Suppose one secant reaches the near point and then the far point , while another reaches then . The relationship is
The symbols look like the intersecting-chords equation, but the lengths now mean external part times whole secant. If and , the whole length is . If , then , so and the interior part .
For a tangent and a secant through from the same external point,
With external part and interior part , the tangent length is . This statement concerns segment lengths, not angles. The AMSI circle module develops these relationships through similarity.
Choosing a theorem from the givens
First identify whether the known point lies inside, on or outside the circle. Next label the complete lines and the segment endpoints. For a chord-distance problem, draw the perpendicular radius to expose a right triangle. For two external lines, mark the near and far intersections before forming a product.
Treat the sketch as a record of the hypotheses. An apparently tangent line needs a stated tangency condition or a proof that it is perpendicular to the radius at a boundary point. A diagram touching the curve on screen is not itself evidence.
Practice questions
- A radius- circle has a chord from its centre. Find the chord length.
- Intersecting chords have segment lengths and . Find .
- A secant from an external point has external part and whole length . Find the tangent length from that point.
Check your answers
- Half the chord is , so the whole chord is .
- , so .
- , so the positive tangent length is . Do not add to : the whole length was already supplied.
Related topics
Angles in Circles explains the inscribed-angle facts used in the similarity argument. Chords, Arcs and Sectors separates straight chord length from curved arc length and region area.
Sources and further reading
- AMSI, Circle Geometry: chord, tangent and secant theorems.
- Euclid, Elements III.3: a chord and the perpendicular through its midpoint.
- Euclid, Elements III.36: the tangent-secant relationship.
