A quadratic expression in one variable has highest exponent 2 and can be written as a x 2 +bx+cax^{2} + bx + c with a≠0a \ne 0. It is an expression until it is set equal to another quantity.

Different equivalent forms reveal different information. Standard form shows coefficients; factored form shows potential zeros; completed-square form shows the vertex and minimum or maximum when the expression defines a function.

On this page (8 sections)

Standard form and its parts

a x 2 +bx+c, a≠0ax^2+bx+c,\qquad a\ne0

The coefficient aa is the leading coefficient, bb is the linear coefficient and cc is the constant term. Here aa, bb and cc are real constants. A missing linear or constant term simply has coefficient zero.

For example, 4 x 2 +74x^2+7 is quadratic with b=0b=0. The expression 0 x 2 +4x+70x^2+4x+7 is linear, not quadratic. Identify degree after simplifying, since apparently quadratic terms can cancel.

Evaluating a quadratic expression

For x 2 −4x+3x^2-4x+3 at x=5x=5, substitute into every occurrence of the variable.

5 2 −4(5)+3=25−20+3=85^2-4(5)+3=25-20+3=8

If the input were −1-1, parentheses would give (−1 ) 2 −4(−1)+3=1+4+3=8(-1)^2-4(-1)+3=1+4+3=8. Different inputs can yield the same value.

Equivalent forms reveal different structure

Three equivalent forms of the same quadratic
FormExpressionInformation visible
Standard x 2 +x−6x^2+x-6Leading, linear and constant coefficients
Factored (x−2)(x+3)(x-2)(x+3)Zeros at 22 and −3-3 when the expression is set equal to zero
Completed square (x+ 1 2 ) 2 − 25 4 (x+\frac12)^2-\frac{25}{4}Minimum value −25 / 4-25/4 attained at x=−1 / 2x=-1/2
(x−2)(x+3)= x 2 +x−6(x-2)(x+3)=x^2+x-6
( x + 1 2 ) 2 − 25 4 = x 2 +x+ 1 4 − 25 4 = x 2 +x−6\left(x+\frac12\right)^2-\frac{25}{4}=x^2+x+\frac14-\frac{25}{4}=x^2+x-6

Both expansions return the standard form, so these are three representations of the same expression. The most useful representation depends on whether you need coefficients, zeros or a minimum.

Expression, equation and function are different roles

x 2 −4x+3x^2-4x+3 is an expression. The statement x 2 −4x+3=0x^2-4x+3=0 is an equation, whose real solutions are 11 and 33. The rule f(x)= x 2 −4x+3f(x)=x^2-4x+3, together with a domain, defines a function.

The algebra is related, but the tasks differ: evaluate or rewrite the expression, solve the equation, or describe the outputs and graph of the function.

Connection to quadratic functions

For the function f(x)= x 2 −4x+3f(x)=x^2-4x+3, completing the square gives f(x)=(x−2 ) 2 −1f(x)=(x-2)^2-1. Its graph is a parabola with vertex (2,−1)(2,-1) and symmetry line x=2x=2.

Read the zeros and the minimum from the same quadratic

Read the zeros and the minimum from the same quadraticThe parabola is symmetric about x = 2. Outputs decrease to −1 and then increase. The two roots lie one unit on either side of the symmetry line.−1012345−202468xy(1, 0)(3, 0)(2, −1)
  • y= x 2 −4x+3=(x−2 ) 2 −1y=x^2-4x+3=(x-2)^2-1
The zeros are 11 and 33; the minimum point is (2,−1)(2,-1).
Diagram explained

The parabola is symmetric about x = 2. Outputs decrease to −1 and then increase. The two roots lie one unit on either side of the symmetry line.

Exact reference values for this graph
InputOutput
00 33
11 00
22 −1-1
33 00
44 33

Since (x−2 ) 2 ≥0(x-2)^2\ge0, the least output is −1-1, attained at x=2x=2. The roots 11 and 33 sit equally far from the symmetry line. These features connect the expression to its graph without requiring calculus.

Practice questions

  1. Is 4 x 2 −x+74x^{2} – x + 7 quadratic?

  2. Evaluate x 2 −4x+3x^{2} – 4x + 3 at x=5x = 5.

  3. Expand (x−2)(x+3)(x – 2)(x + 3).

Check your answers
  1. Yes. In 4 x 2 −x+74x^2-x+7, the highest power is 2 with non-zero coefficient 4.

  2. 5 2 −4(5)+3=25−20+3=85^2-4(5)+3=25-20+3=8.

  3. (x−2)(x+3)= x 2 +3x−2x−6= x 2 +x−6(x-2)(x+3)=x^2+3x-2x-6=x^2+x-6.

Related topics

Set a quadratic expression equal to zero in Quadratic Equations, then learn how Completing the Square reveals its vertex.

Sources and further reading